Jessie Said:

Can someone please help me with these word problems for pre-algebra?

We Answered:

1
Let x = number of basketball shoes
Let y = number of tennis shoes

You have and need two equation to solve a two variable problem

2x = y (twice as many basketball shoes as tennis shoes)

x+ y = 96 (total amount of all of the shoes are 96 pairs)

Use the substitution method to solve

x + (2x) = 96 (since y = 2x)

3x = 96
now divide each side by 3

3x/3 = 96/3

x = 32 That is the amount of basketball shoes. Use you either equation to find out how many tennis shoes

2x = y

2(32) = 64

#2

Let x = Saturday Words and y = Sunday Words

x + y = 512

also

x + 180 = y or y - 180 =x they mean the same thing

So again using substitution
x+ (x+180) = 512

2x +180 = 512

2x = 512 - 180 = 332

x = 332/2 = 166

y = 512 - 166 = 346

Nicholas Said:

Can someone help me in these pre-algebra problems?

We Answered:

Maybe the expressions are to be simplified:
1st problem:
= 8(5 - n) - 19 + 17n - 21
= 40 - 8n + 17n - 40
= 9n

Answer: 9n

2nd problem:
= 7(3f - 2g) - 14(g - f)
= 21f - 14g - 14g + 14f
= 35f - 28g

Answer: 35f - 28g OR 7(5f - 4g)

Another way of simplifying:
= 7(3f - 2g) - 14(g - f)
= 7(3f - 2g - 2[g - ]f)
= 7(3f - 2g - 2g + 2f)
= 7(5f - 4g) or 35f - 28g

Lucy Said:

How to solve these pre algebra problems?

We Answered:

1. A strip of wood 66 inches long is to be cut into 5 1/2 pieces . How many pieces can be cut ?
Assuming you mean each piece is 5 1/2 inches long, just divide 66 by 5 1/2.

2. A piece of pipe is 30 3/4 inches long. If five pieces, each 4 1/3 long, are cut from the pipe, how many inches of pipe remains?
Multiply 4 1/3 by 5 to get the total length of the 5 pieces. Then subtract that number from 30 3/4 to get the answer.

3. If 3 1/2 pounds of bananas cost $.98, how much would one pound cost?
Divide $.98 by 3 1/2.

Pearl Said:

does anyone know of a free sight to figure out pre-algebra problems? 5-4y+y+7=?

We Answered:

Are you supposed to solve for y?

12-3y = ?
-3y = -12
y = 4

Jacob Said:

Help with pre algebra problems please?

We Answered:

3x + 13 = 22
3x = 22 - 13
3x = 9
x = 9/3 or 3

Answer: x = 3
-----------
2y + 9 = 19
2y = 19 - 9
2y = 10
y = 10/2 or 5

Answer: y = 5

Max Said:

Pre Algebra word problems-need help solving worth 100 points ?

We Answered:

HINT: Write what you know.

~~~~~~~~~~~~~~~~~~~~~~~~`

A 53 foot piece of metal is cut into 4 pieces. The first two pieces are the same. The board is cut so that the length of the third piece is four times as long as the first piece and the fourth piece is 5 more than 3 times the second piece. Find the length of all four pieces.

Variables:
a = 1st length
b = 2nd length
c = 3rd length
d = 4th length

Given: A 53 foot piece of metal is cut into 4 pieces.
Means: a + b + c + d = 53

Given: The first two pieces are the same.
Means: a = b
Means: a + a + c + d = 53 = 2a + c + d

Given: the length of the third piece is four times as long as the first piece
Means: c = 4a
Means: 2a + 4a + d = 53 = 6a + d

Given: the fourth piece is 5 more than 3 times the second piece.
Means: d = 3a + 5
Means: 6a + 3a + 5 = 53 = 9a + 5

Solve.
53 = 9a + 5
53 - 5 = 9a + 5 - 5
48 = 9a
48 / 9 = 9a / 9
a = 48 / 9 = 16 / 3 = 5 1/3

a = 5 1/3
b = a = 5 1/3
c = 4a = 4(16 / 3) = 64 / 3 = 21 1/3
d = 3a + 5 = 3(16 / 3) + 5 = 16 + 5 = 21

ANSWER:

Length of Pieces:
1: 5 1/3 feet
2: 5 1/3 feet
3: 21 1/3 feet
4: 21 feet

Equation: 9a + 5 = 53

CHECK:
a + b + c + d = 53
(16 / 3) + (16 / 3) + (64 / 3) + 21 = 53?
[(16 + 16 + 64) / 3] + 21 = 53?
(96 / 3) + 21 = 53?
32 + 21 = 53?
53 = 53?
true

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The length of a rectangular parking lot is 20 feet less than twice its width. The perimeter of the lot is 460 feet. Find the length and width of the lot.

Variables:
L = length
W = width

Given: The length of a rectangular parking lot is 20 feet less than twice its width.
Means: L = 2W - 20

Given: The perimeter of the lot is 460 feet.
Implied: You know the perimeter formula.
Means: P = 2(L + W) = 460

You have 2 equations.
L = 2W - 20
2(L + W) = 460

Substitute L with 2W - 20 in the second equation.
2(L + W) = 460
2(2W - 20 + W) = 460
2(3W - 20) = 460
2(3W) + 2(-20) = 460
6W - 40 = 460
6W - 40 + 40 = 460 + 40
6W = 500
W = 500 / 6 = 250 / 3 = 83 1/3

Plug this into the first equation to find L.
L = 2W - 20
L = 2(250 / 3) - 20
L = (500 / 3) - 20
L = (500 / 3) - 20(3 / 3)
L = (500 / 3) - (60 / 3)
L = (500 - 60) / 3
L = 440 / 3 = 146 2/3

ANSWER: The length is 146 2/3 feet; the width is 83 1/3 feet.

CHECK:
L = 2W - 20
(440 / 3) = 2(250 / 3) - 20?
(440 / 3) = (500 / 3) - 20?
(440 / 3) = (500 / 3) - 20(3 / 3)?
(440 / 3) = (500 / 3) - (60 / 3)?
(440 / 3) = (500 - 60) / 3?
(440 / 3) = (440 / 3)?
true

2(L + W) = 460
2[(440 / 3) + (250 / 3)] = 460?
2[(440 + 250) / 3] = 460?
2(690 / 3) = 460?
2(230) = 460?
460 = 460?
true

Jeanette Said:

does anybody know of a free site to figure out pre algebra problems?

We Answered:

Ya there's one called Yahoo! Answers